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The fn:contains() function determines whether an input string contains a specified substring.
Syntax:
The fn:contains() function has following syntax:
boolean contains(java.lang.String, java.lang.String)
Example:
Following is the example to explain the functionality of this function:
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %> <%@ taglib uri="http://java.sun.com/jsp/jstl/functions" prefix="fn" %> <html> <head> <title>Using JSTL Functions</title> </head> <body> <c:set var="theString" value="I am a test String"/> <c:if test="${fn:contains(theString, 'test')}"> <p>Found test string<p> </c:if> <c:if test="${fn:contains(theString, 'TEST')}"> <p>Found TEST string<p> </c:if> </body> </html>
This would produce following result:
Found test string
source - http://www.tutorialspoint.com/jsp/jstl_function_contains.htm
reference - http://docs.oracle.com/javaee/5/jstl/1.1/docs/tlddocs/fn/tld-summary.html
boolean contains(java.lang.String, java.lang.String)
첫번째 매개변수 타입으로 ArrayList도 가능
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spring - How to respond with HTTP 400 error in a Spring MVC @ResponseBody method returning String?
Framework & Platform/Spring 2014. 7. 9. 14:43How to respond with HTTP 400 error in a Spring MVC @ResponseBody method returning String?
I'm using Spring MVC for a simple JSON API, with @ResponseBody based approach like the following. (I already have a service layer producing JSON directly.)
@RequestMapping(value = "/matches/{matchId}", produces = "application/json")
@ResponseBody
public String match(@PathVariable String matchId) {
String json = matchService.getMatchJson(matchId);
if (json == null) {
// TODO: how to respond with e.g. 400 "bad request"?
}
return json;
}Question is, in the given scenario, what is the simplest, cleanest way to respond with a HTTP 400 error?
I'm new to Spring MVC, and this turned out somewhat non-obvious... I did come across approaches like:
return new ResponseEntity(HttpStatus.BAD_REQUEST);...but I can't use it here since my method's return type is String, not ResponseEntity.
Answers
change your return type to ResponseEntity<String>, then you can use below for 400
return new ResponseEntity<String>(HttpStatus.BAD_REQUEST);and for correct request
return new ResponseEntity<String>(json,HttpStatus.OK);Something like this should work, I'm not sure whether or not there is a simpler way:
@RequestMapping(value = "/matches/{matchId}", produces = "application/json")
@ResponseBody
public String match(@PathVariable String matchId, @RequestBody String body,
HttpServletRequest request, HttpServletResponse response) {
String json = matchService.getMatchJson(matchId);
if (json == null) {
response.setStatus( HttpServletResponse.SC_BAD_REQUEST );
}
return json;
}source - http://stackoverflow.com/questions/16232833/how-to-respond-with-http-400-error-in-a-spring-mvc-responsebody-method-returnin
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