spring data jpa - Unable to build EntityManagerFactory
Framework & Platform/Spring 2013. 1. 5. 11:57Ask
persistence.xml file
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="xyz" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com......</class>
</persistence-unit>
</persistence>
ApplicationContext.xml
<bean id="transactionManager"
class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
<property name="url" value="jdbc:oracle:thin:@localhost:1521:XE" />
<property name="username" value="yyy" />
<property name="password" value="yyy" />
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="xyz" />
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter">
<bean
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform" value="org.hibernate.dialect.Oracle10gDialect" />
<property name="showSql" value="true" />
<!-- <property name="generateDdl" value="true" /> -->
</bean>
</property>
</bean>
<bean id="theDao" class="com.cin.the.dataaccess.dao.the.TheJPA">
<property name="entityManagerFactory" ref="entityManagerFactory"></property>
</bean>
the error i get is
[PersistenceUnit: xyz] Unable to build EntityManagerFactory
Answer
The main problem was that the entites was not generated properly. so at the end of the stacktrace it was giving this error
Caused by: org.hibernate.MappingException: property mapping has wrong number of columns: com......date type: object
once the entity was generated correctly the problem was solved
나의 경우 entity와 실제 table를 매핑 시키지 않았음. 그래서 다음처럼 매핑 시킴
< before >
@Entity
public class SomeEntity {
...
}
< after >
@Entity
@Table(name="tableName")
public class SomeEntity {
...
}
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